Question 174720


{{{(x+5)(3x-2)(23x)=0}}} Start with the given equation




Now set each factor equal to zero (by use of the zero product property):



{{{x+5=0}}}, {{{3x-2=0}}} or {{{23x=0}}}



Now solve for x for each factor:



{{{x=-5}}}, {{{x=2/3}}} or {{{x=0}}}



So the solutions of {{{(x+5)(3x-2)(23x)=0}}} are {{{x=-5}}}, {{{x=2/3}}} or {{{x=0}}}