Question 174643
This is what you stated:

Solve the equation: watch for extraneous solutions: 
5 = y+7 +1
y-3 2y-6

Now, y - 3 2y - 6 does not make sense.

There is a missing equal sign.

Where does the equal sign go in the case of y-3 2y-6?

Write back and I'll be able to complete this question for you.

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I received your e-mail.

I'm sorry but you are not clear in your expression.
 
Do you want to solve for y?
 
Here is the fractional equation that I made based on what you said:
 
[5/(y - 3)] = (y + 7)/(2y - 6)
 
Is this what you meant to type?
 
Where does 1 belong in your equation?
 
If this is what you need solved, then write back.