Question 174658
I am changing my answer: since 90% of the mixture is 100% water then 50% of the mixture is 55.56% water...therefore we lost  44.44% of the weight or retained 55.56% of its weight
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.5556(20)=11.112 pounds....

 that being said the water had to evaporate......I believe the assumption is that the other part of the mixture doesnt evaporate.
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Very strange problem as the mixture could be 90% by weight or volume....alot of questions on this problem.....imo it isnt written very well.

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If someone has a better explanation I hope they post it......