Question 174619
hows it going recently i have begun getting myself evrolled for school and going over math i havent done in 3 or so years so i picked up an algebra review book but nither it nor the internet has shown me how to do the following three equations. im hoping someone can help me. 
y=(x-2)^2+1 

2) x/3+y/5=2 
3) 3/x-2=y+4/2 
----------------
You didn't say what you want to do.  Often, it's "solve for x", so I'll do that.  It would be better if you specified, tho, and not waste my time and yours.
-----------------
y=(x-2)^2+1 
(x-2)^2 = y-1
x-2 = sqrt(y-1)
{{{x = sqrt(y-1) + 2}}}
---------------------
x/3+y/5=2
Multiply thru by 15 to eliminate fractions
5x + 3y = 30
5x = 30-3y
x = (30-3y)/5
----------------
3/x-2=y+4/2
Do you mean 3/(x-2) = (y+4)/2 ? It could (3/x)-2 = y+(4/2) I'll assume the 1st.
3/(x-2) = (y+4)/2
With 2 fractions, the quickest way is to "cross multiply", the NUM of one times the DEN of the other.
3*2 = (x-2)*(y+4)
6/(y+4) = x-2
x = 2 + (6/(y+4))  Notice how the parentheses eliminate any ambiguities.  And they're free.