Question 174607
A)
:
6x+2y=2.....eq 1
3x+5y=5.....eq 2
:
multiply eq 2 by -2
:
6x+2y=2.....eq 1
-6x-10y=-10.eq 2 revised
:
now add the two equations together. As you can see the x terms are eliminated because 6x-6x=0.  We are left with 2y-10y=2-10
:
-8y=-8
:
{{{highlight(y=1)}}}
:
now substitute our found value of y into either eq 1 or 2 and solve for x. I choose eq 1
:
6x+2(1)=2
:
6x+2=2
6x=0
:
{{{highlight(x=0)}}}
:
ordered pair solution is (0,1)



B)lets re write these equations in point intercept form
:
-3y=-4x+1--->y=(4/3)x-1/3
:
9y=12x+5--->y=(4/3)x+5/9
:
as one can see the slopes are equal which means these lines are parallel to one another therefore NO solutions