<PRE><B>Question 174602</B>
let x be the original number going on trip and y be the new number of trip goers....and y=x-6

{{{(1800/x)+10=1800/(x-6)}}}
:
{{{1800x=1800(x-6)+10(x^2-6x)}}}multiplied all terms by {{{x(x-6)=x2-6x)}}}
:
{{{1800x=1800x-10800+10x^2-60x}}}distributing
:
{{{10x^2-60x-10800=0}}}combining terms
:
{{{x^2-6x-1080=0}}}divided all terms by 10
:
using the quadratic formula we arrive at x=36 and -30
:
throwing out the negative value
:
{{{x=36}}}original trip goers
:
{{{highlight(y=36-6=30)}}}those who went on trip

 *[invoke solve_quadratic_equation 1, -6, -1080]</PRE>