Question 174538
2(x+1)^2+14(x+1)+20=0


Factor out the common factor of 2, or, better yet, divide both sides by 2:
(x+1)^2+7(x+1)+10=0


This factors into
((x+1) +5)*((x+1) + 2)=0
(x+6)(x+3)=0
x=-6 or x= -3


I don't see the correct answer here.  Did you copy the multiple choices correctly???  Also, there are other methods to solve this, in case I confused you with this solution.


ALTERNATE SOLUTION (for anyone who did not understand the above solution!)
{{{ (x+1)^2+7(x+1)+10=0}}}

{{{ x^2 + 2x + 1 + 7x+7 +10 =0}}}
{{{x^2 + 9x + 18=0}}}


This trinomial factors into the product of two binomials:
{{{ (x+6)(x+3)=0}}}

x= -6 or x = -3


Different method, same solution!!  I KNOW this is correct!!  The given answers are WRONG!!


R^2