Question 174456
{{{sin2u* cos2u* tan2u}}}
{{{sin2u* cos2u* ((sin2u)/(cos2u))}}}
{{{(sin 2u)^2 }}}
{{{(2sinu*cosu)^2 }}}
{{{4 (sin u)^2 * (cos u)^2}}}, where {{{(cos u)^2=4/9}}} and {{{(sin u)^2 = 1-(cos u)^2 = 5/9 }}}
 

Now, {{{4 (sin u)^2 * (cos u)^2}}}, 
{{{4*(5/9)*(4/9) }}}
{{{80/81}}}


Please note, I haven't taught trig in about 20 years!!  I'm a bit rusty I'm afraid!!


R^2