Question 174479
Number of Beers (B) = 5 times number of football games (F), or B = 5F.
But suppose you drink 2 beers each day irrespective of football, but there is teo games that day:

Number of beers (B) is 2+4x number of football games, or B=2+4F
Therefore (B)=2+4(10) which leads to the solution.

(B=42) Therefore there was 42 beers drunk during the time of the (2)football games.