Question 174426
c=x+8
b=x
a=x+7
find x
i tried everything i could..i cudnt find any solutions and it drove me crazy...help would be soo appreciated.
<pre><font size = 4 color = "indigo"><b>

There are infinitely many solutions.

1. Pick any number you want for x to be.
2. Add 8 to what you picked for x and you have c.
3. b is that same number you picked for x.
4. Add 7 to what you picked for x and you have a.

Suppose you pick x=4.
Then add 8 and you have c=12
Then b is the same as x, so b=4
Then add 7 to the 4 you picked for x and so a=11.

So a=11, b=4, c=12, x=4 

Lets check by substituting in

c=x+8
b=x
a=x+7

12=4+8 that checks
4=4 that checks
11=4+7 that checks

------

Suppose you pick x=100.
Then add 8 and you have c=108
Then b is the same as x, so b=100
Then add 7 to the 100 you picked for x and so a=107.

So a=107, b=100, c=108, x=100 

Lets check by substituting in

c=x+8
b=x
a=x+7

108=100+8 that checks
100=100 that checks
107=100+7 that checks

-------

Suppose you pick x=-7.3689
Then add 8 and you have c=.6311
Then b is the same as x, so b=-7.3689
Then add 7 to the -7.3689 you picked for x and so a=-.3689

So a=-.3689, b=-7.3689, c=.6311, x=-7.3689 

Lets check by substituting in

c=x+8
b=x
a=x+7

.6311=-7.3689+8 that checks
-7.3689=-7.3689 that checks
-.3689=-7.3689+7 that checks

There are infinitely many solution sets for a,b,c,x.

There's not just one.

Edwin</pre>