Question 174425
lets call the number of nickels and dimes , n and d, respectively
:
n+d=20...........eq 1
.05n+.1d=1.35....eq 2
:
lets rewrite eq 1 to n=20-d and plug this value into eq 2
:
.05(20-d)+.1d=1.35
:
1-.05d+.1d=1.35
:
.05d=.35
:
{{{highlight(d=7)}}}dimes
:
{{{n=20-d=20-7=highlight(n=13)}}}nickels