Question 174383
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{{{2w(4w+1)=1}}}, EQN 1
{{{8w^2+2w-1=0}}}
By Quadratic:
where------->{{{system(a=8,b=2,c=-1)}}}
Then, remember {{{w=x}}}
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}
{{{x=(-2+-sqrt(2^2-4*8*-1))/(2*8)}}}
{{{x=(-2+-sqrt(4+32))/16=(-2+-sqrt(36))/16=(-2+-6)/16}}}
{{{x=(-2+6)/16=4/16=1/4=highlight(0.25=x=w)}}}
{{{x=(-2-6)/16=-8/16=-1/2=highlight(-0.50=x=w)}}}
check in EQN 1:
{{{2(0.25)(4*0.25+1)=1}}}
{{{0.50(1+1)=1}}}
{{{0.50*2=1}}}
{{{1=1}}}
thank you,
Jojo</pre>