Question 174362
Find an equation of the line that is parallel to the line y=-4/3x+7 and that passes through the point (7,3).
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It's not "an equation", it's the equation.  There's only one.
y=-4/3x+7
The slope is -4/3, as the eqn is in the slope-intercept form.
Any line parallel to it will have the same slope.
So,
y-y1 = m*(x-x1) (m is the slope)
y-3 = (-4/3)*(x-7)
3y-9 = -4*(x-7)
3y-0 = -4x+28
4x+3y = 28