Question 174247
So I believe you would say this as "the sixth root of the square root of 2 minus the twelfth root of 2 to the thirteenth power". Are you supposed to estimate this using a calculator? If not, I think the most you can simplify it is 2^(1/12) - 2^(13/12). You can do that because, for instance, the square root of 2 is 2^(1/2). So "the sixth root of the square root of 2" is (the square root of 2)^(1/6), which is (2^(1/2))^(1/6). So you multiply the exponents and get 2^1/12. Then you work similarly with the second part.