Question 174186


{{{abs(8-3x)=2}}} Start with the given equation



Break up the absolute value (remember, if you have {{{abs(x)=a}}}, then {{{x=-a}}} or {{{x=a}}})


{{{8-3x=-2}}} or {{{8-3x=2}}} Set the expression {{{8-3x}}} equal to the original value 2 and it's opposite -2





Now lets focus on the first equation  {{{8-3x=-2}}}



{{{-3x=-2-8}}}Subtract 8 from both sides



{{{-3x=-10}}} Combine like terms on the right side



{{{x=(-10)/(-3)}}} Divide both sides by -3 to isolate x




{{{x=10/3}}} Reduce





<hr>


Now lets focus on the second equation {{{8-3x=2}}}




{{{-3x=2-8}}}Subtract 8 from both sides



{{{-3x=-6}}} Combine like terms on the right side



{{{x=(-6)/(-3)}}} Divide both sides by -3 to isolate x




{{{x=2}}} Divide






So the solutions are:


{{{x=10/3}}} or {{{x=2}}}