Question 173883
{{{y = log(2,(x^(-1)))}}}
I can rewrite this as
{{{2^y = 1/x}}}
If I plot 
{{{2^x = 1/y}}}
{{{y = 2^(-x)}}}
instead, this
is the inverse function and will be symmetrical
with the original function  about {{{y = x}}}.
I'll plot both to prove it
{{{ graph( 600, 600, -10, 10, -10, 10,log(2,1/x), 2^(-x)) }}}
As for which is which, The {{{y = 2^(-x)}}} has the points
(-1,2), (0,1), (1,1/2)
You can apply this method to the others also