Question 174137
{{{(3sqrt(2))^5=3^5(sqrt(2)sqrt(2)sqrt(2)sqrt(2)sqrt(2))}}} now since {{{sqrt(2)sqrt(2)}}}=2........we can take a 2 outside the radical for every 2 {{{sqrt(2)}}}'s that we see. that means (2)(2)=4,which we multiply by {{{3^5}}} and whats left is 1, {{{sqrt(2)}}}
:
{{{3^5(4)sqrt(2)=972sqrt(2)}}}