Question 174025
Ok, well if all the sides are consecutive even integers they can be written as follows:

2n
2n + 2
2n + 4

So, the perimeter is 2n + (2n + 2) + (2n + 4) or 6n + 6

Since the longest side is 2n + 4 and it is 22 units shorter than the perimeter we have,

(2n + 4) + 22 = 6n + 6
2n + 26 = 6n + 6
2n = 6n - 20
-4n = -20
n = 5

The longest side is 2n + 4 and n = 5 so 2(5) + 4 = 14 is the longest side.

Thus, the triangle has sides, 10, 12, 14.