Question 174089
I think the problem is as shown below. You need to be 'really careful'. Is that correct? Do yourself a favor and don't be stingy with parens

{{{3w- 2((w-4)/3) = 1/3 }}}  multiply everything by 3 to clear the denominators
{{{9w - 2(w-4) = 1}}}
{{{9w - 2w + 8  = 1}}}
{{{7w = -7}}}
{{{w = -1}}}