Question 174087
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Line 1 {{{2x - 4y = 8}}}.
Arranging to follow Slope-intercept form:
{{{4y=2x-8}}}---->{{{cross(4)y/cross(4)=(2x-8)/4=(2/4)x-(8/4)}}}
{{{y=highlight((1/2))x-2}}}
It shows has a {{{Slope=m[1]=1/2}}}
We know when lines are perpendicular:{{{m[2]=-1/m[1]}}}
Then Line 2 has {{{Slope=m[2]=-1/(1/2)=-2}}}
It follows: {{{highlight(y=-2x-9)}}} OR {{{highlight(2x+y=-9)}}} Standard Form (Answer)
we see the graph:
{{{drawing(300,300,-10,10,-10,10,grid(1),graph(300,300,-10,10,-10,10,(1/2)x-2,-2x-9))}}}-------> RED, Line 1: GREEN, Line 2
Thank you,
Jojo</pre>