Question 174052
The first thing you need to know is that the slopes of perpendicular lines have a product of -1.
y = mx +b. The slope of the given line is 3 (since the line is given as  Y= 3X+2)
So the slope of the lines perpendicular to that line is -1/3

*[invoke equation_parallel_or_perpendicular "perpendicular", 3, 2, 1, -1]