Question 174039
Write an equation of the line that passes through the given point and is perpendicular to the given line.
(1,-1), y=3x+2
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Since the given slope is 3, the slope you want is -1/3.
Equation form is y = mx +b
Substitute to solve for "b":
-1 = (-1/3)*1 + b
b = -1 + (1/3) = -2/3
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Equation:
y = (-1/3)x + (-2/3)
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Cheers,
Stan H.