Question 174012
The equation (of the line you want to be parallel with) was given as:
y= 5x-3
This is in the "slope-intercept" form:
y = mx + b
where
m is slope
b is the y-intercept
.
From the above, we now know the slope of:
y= 5x-3
is
m = 5
.
For two lines to be parallel, both of their slopes must be the same. Therefore, our "new" line mus have the slope of 5.
.
Given that we know the slope (5) and a single point (4,7) we stuff that into the "point slope" equation:
y - y1 = m(x - x1)
y - 7 = 5(x - 4)
Now, we manipulate to back into the "slope intercept" form:
y - 7 = 5x - 20
y = 5x - 13 (this is what they're looking for)