Question 173943
(X^2-2X)/(X^2-9) > 0
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When you are asked to graph an inequality you
must first graph the equality which is the boundary
of the inequality.  Then you must determine which  
area determined by the boundary contains the solutions
for the inequality. 
Here is the boundary:
{{{graph(400,300,-10,10,-10,10,(x^2-2x)/(x^2-9))}}}
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Since you want "greater than" the area you want is 
all the points above the boundary.
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Cheers,
Stan H.