Question 172461
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{{{y=(x+1)^2-7}}}--->{{{a(x-h)^2+k}}}
where h,k is the vertex:
Then, {{{h=x=-1}}}; {{{k=y=-7}}}
{{{F(x)=0}}}
{{{y=(0+1)^2-7=1-7=-6}}}
{{{F(y)=0}}}
{{{7=(x+1)^2}}}
{{{sqrt(7)=x+1}}}
{{{x=-1+-sqrt(7)=-1+-2.646}}}
{{{x=-3.646}}},{{{x=1.646}}}
.
{{{y=(x-4)^2-2}}}
{{{h=x=4}}};{{{k=y=-2}}}
{{{F(x)=0}}}----->{{{y=(0-4)^2-2=16-2=14}}}
{{{F(y)=0}}}--->{{{sqrt(2)=x-4}}}
{{{x=4+-sqrt(2)}}}
{{{x=4+1.414=5.414}}}
{{{x=4-1.414=2.586}}}
{{{drawing(500,500,-10,10,-10,16,grid(1),graph(500,500,-10,10,-10,16,(x+1)^2-7,(x-4)^2-2),blue(circle(-1,-7,.10)),blue(circle(4,-2,.10)),circle(0,14,.10),circle(0,-6,.10),circle(-3.646,0,.10),circle(1.646,0,.10),circle(5.414,0,.10),circle(2.586,0,.10))}}}-->RED {{{y=(x+1)^2-7}}}, GREEN {{{y=(x-4)^2-2}}}
Thank you,
Jojo</pre>