Question 173927
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{{{y=x^2-3}}}
Let's see the points on the graph:
{{{f(y)=x^2-3}}}
{{{f(0)=0^2-3=-3}}} ------>(0,-3)
{{{f(1)=1^2-3=1-3=-2}}}------->(1,-2)
{{{f(2)=2^2-3=4-3=1}}}-------->(2,1)
{{{f(-1)=-1^2-3=1-3=-2}}}----->(-1,-2)
{{{f(-2)=-2^2-3=4-3=1}}}------>(-2,1)
Let's draw the graph then thru the points:
{{{drawing(300,300,-6,6,-6,6,grid(1),graph(300,300,-6,6,-6,6,x^2-3),blue(circle(0,-3,.15)),blue(circle(1,-2,.15)),blue(circle(2,1,.15)),blue(circle(-1,-2,.15)),blue(circle(-2,1,.15)))}}}
Thank you,
Jojo</pre>