Question 173684
Given f(x) = some function of x, to evaluate f(a), just substitute a for x whereever it occurs in the function and do the arithmetic.  I presume D stands for domain, so since all of your values are integers, you don't have any excluded values in any of the stated domains.


Here's how to do the first one:

Given that {{{f(x) = x^2 + 3}}} and D = {reals}, find {{{f(-3)}}}.


{{{f(-3)=(-3)^2+3=9+3=12}}}


Do the rest of them the same way.