Question 173853
I need to find an equation of the line that is parallel to the line y=7x-3 and passes thru the point (8,7).
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okay, {{{slope=m}}} of line {{{y=7x-3}}} is {{{m[1]=7}}}. Since the line are parallel, {{{m[1]=m[2]=7}}}.
Therefore, thru point (8,7), we can get the y-intercept via Slope-intercept Form: {{{y=mx+b}}}
{{{7=7*8+b}}}
{{{7=56+b}}} ----->{{{b=7-56=-49}}}, y-intercept.
Then, line eqn is----->{{{highlight(y=7x-49)}}}, or {{{highlight(-7x+y+49=0)}}} Standard Form
We see the graph:
{{{drawing(400,400,-10,10,-55,20,grid(1),graph(400,400,-10,10,-55,20,7x-3,7x-49),blue(circle(8,7,.20))))}}} -------> RED, Line {{{y=7x-3}}}; GREEN, Line {{{y=7x-49}}}
Thank you,
Jojo</pre>