Question 173810
L = 3/(x+4)
w = 2/(x-5)
PERIMETER=2L+2W
P=2[3/(X+4)]+2[2/(X-5)
P=6/(X+4)+4/(X-5)
P=[6(X-5)+4(X+4)]/(X+4)(X-5)
P=(6X-30+4X+16]/(X+4)(X-5)
P=(10X-14)/(X+4)(X-5)
P=2(5X-7)/(X+4)(X-5) IS THE PERIMETER.
AREA=L*W
AREA=3/(X+4)*2/(X-5)
AREA=6/(X^2-X-20) IS THE AREA.