Question 173790
(1) 16x-6y = -28
(2) 4x+12y = 14

Dividing (2)'s coefficients in half:

(1) 16x-6y = -28
(3)  2x+6y = 7

Adding (1) and (3) cancels the 'y' term:

(4) 18x = -21

Dividing by 18 we get the value of x:

(5) x = -21/18 = -7/6

Substituting into (3):

(6) 2(-7/6) + 6y = 7
or -7/3 + 6y = 7

solving for y:

6y = 7 + 7/3 = (21/3) + (7/3) = 28/3

y = 28/18 = 14/9

Solution:  x=-7/6 and  y =14/9
Verifying:

(1) 16x-6y = 16(-7/6) - 6(14/9) = -(56/3)-(28/3) = -84/3 = -28 , it works

(2) 4x+12y = 4(-7/6) + 12(14/9) = -(14/3) + (56/3) = (56-14)/3 = 42/3 = 14 , it works, too.