Question 173641
since the focus is to the left of the vertex and the line of symmetry is y=-2
then this parabola has to take the form of {{{y^2=x}}} and has to open to the left. furthermore since we know the vertex we can plug in that info
:
{{{(y+2)^2=4p(x+4)}}} so now all we have to do is figure out what p is....since the focus is a distance of 2 units to the left of the vertex this means p=-2
:
4(-2)=-8
:
so we have a final equation of
:
{{{highlight(y+2)^2=-8(x+4)}}}