Question 172331
the sum of three numbers is 123. the second number is 9 less than two times the first number. the third number is 6 more than three times the first numner. what are the three numbers?
--------------------------------
Equations:
x   +  y   +   z   =  123
y = 2x-9
z = 3x+6
----------------------------
x   +  y   +   z   =  123
2x  -  y   +   0   =    9
3x  +  0   -   z   =   -6
----------------------------
Solve by any method you know to get:
x = 21
y = 33
z = 69
==========================
Cheers,
Stan H.