Question 173573
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{{{5^(t-1)=3.92}}}, working eqn
{{{(t-1)log5=log3.92}}}-------->{{{(t-1)cross(log5)/cross(log5)=log3.92/log5}}}
{{{t=1+0.8488}}}
{{{highlight(1.8488)}}}
Check via working eqn:
{{{5^(1.8488-1)=3.92}}}
{{{5^0.8488=3.92}}}
{{{3.91997=3.92}}}, close enough
Thank you,
Jojo</pre>