Question 173700
{{{abs(4a+3)<=5}}} means that {{{4a+3<=5}}} and {{{-(4a+3)<=5}}}, so:


{{{4a+3<=5}}} &#8594; {{{4a<=2}}} &#8594; {{{a<=2/4}}} &#8594; {{{a<=1/2}}}


and


{{{-(4a+3)<=5}}} &#8594; {{{-4a-3<=5}}} &#8594; {{{-4a<=8}}} &#8594; {{{a>=8/(-4)}}} (Note inequality sense change because of dividing by a negative number)  &#8594; {{{a>=-2}}}


Therefore {{{a}}} is any real number in the interval {{{-2<=a<=1/2}}}