Question 173677
(-1,-3), (2,-1)
first,we find the {{{Slope=m}}} thru given points:
Via Slope Form:
{{{m=(y[2]-y[1])/(x[2]-x[1])}}}
where--->{{{system(y[2]=-1,y[1]=-3,x[2]=2,x[1]=-1)}}}
Then,
{{{m=(-1-(-3))/(2-(-1))=(-1+3)/(2+1)=2/3}}}
Then, thru points (-1,-3): Via Slope-Intercept--->{{{y=mx+b}}}
{{{-3=(2/3)(-1)+b}}}
{{{-3=(-2/3)+b}}}
{{{b=-3+(2/3)=(-9+2)/3=-7/3}}}
Then,
{{{y=(2/3)x-(7/3)}}}.--->{{{y-(2/3)x=-7/3}}}
{{{(3y-2x)/3=-7/3}}}-->{{{3y-2x=3*(-7/3)}}}
{{{highlight(3y-2x+7=0)}}}
ROUND-OFF
{{{y=1x-2}}}--->{{{-x+y+2=0}}}, Standard form
{{{drawing(300,300,-10,10,-10,10,grid(1),graph(300,300,-10,10,-10,10,(2/3)x-(7/3)),circle(0,-7/3,.15),circle(7/2,0,.15))}}}

Thank you,
Jojo