Question 173673
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First problem:
{{{3x+y=5}}}, EQN 1
{{{-2x+3y=4}}}, EQN 2 
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I'll do the 1st problem, and take care the rest:
In EQN 1,we isolate "y" and get:
{{{y=-3x+5}}}-----> EQN 3, subst. in EQN 2:
{{{-2x+3(highlight(-3x+5))=4}}}
{{{-2x-9x+15=4}}}
{{{-11x=4-15=-11}}}
{{{cross(-11)x/cross(-11)=cross(-11)1/cross(-11)1}}}
{{{highlight(x=1)}}}, subst. in EQN 3:
{{{y=-3(1)+5=-3+5}}}
{{{highlight(y=2)}}}
Check, subst "x" & "y" in EQN 2 (or EQN 1):
{{{-2(1)+3(2)=4}}}
{{{-2+6=4}}}
{{{4=4}}}, good
Thank you,
Jojo</pre>