Question 173657
factoring a 3 out of the first 2 terms and a {{{x^2}}}out of the last two terms we have
:
{{{3(5+y)-x^2(5+y)}}}
:
now factor our a (5+y) term
:
(5+y)(3-x^2)
:
we have a form of differences of squares in {{{3-x^2}}} term if you use radicals
:
{{{(5+y)(sqrt(3)-x)(sqrt(3)+x)}}}
:
that all she wrote