Question 173507
{{{2^(x^2)=32(2^(4x))}}}
{{{2^(x^2)=2^5 * (2^(4x))}}}
{{{2^(x^2)=2^((4x + 5))}}}
{{{x^2 = 4x + 5}}}
{{{x^2 - 4x - 5 = 0}}}
{{{x-5)(x+1)= 0}}}
x = 5 or x = -1

check your answers by plugging these two values into the original equation. See if none, one or both work. let me know if you can't take it in from here