Question 173435
{{{log(5,(1/25))}}}


Remember the definition:  {{{y=log(b,(x))}}} if and only if {{{b^y=x}}}


So:  {{{y=log(5,(1/25))}}}  if and only if {{{5^y=1/25}}}.  Since {{{25=5^2}}}, {{{1/25=5^-2}}}, so {{{y=-2}}}.


Hence:  {{{log(5,(1/25))=-2}}}