Question 173447
a+2c+3E+2F=270
2a+b+2d+2f=240
3a+4b+c+f=360
a+5c+2e=440
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Even assuming the E is the same as e, and F is f, you have 4 equations in 6 unknowns.  That is not sufficient.  You have to have 6 eqns if there are 6 unknowns.