Question 173436
Rule 1:  {{{log(b,(x^n))=n*log(b,(x))}}}, so {{{ln(e^4)=4*ln(e)}}}


Rule 2:  {{{log(b,(b))=1}}}.  Since {{{ln(x)}}} is the same thing as {{{log(e,(x))}}}, {{{ln(e)=1}}}.


Putting it all together:


{{{ln(e^4)=4*ln(e)=4*1=4}}}