Question 173207
2+8sqrt(10) divided by 2-6sqrt(2)
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={{{(2+8sqrt(10))/(2-6*sqrt(2))}}}
={{{(1+4sqrt(10))/(1-3*sqrt(2))}}} Divided by 2
To get the radical out of the DEN, multiply by its conjugate (1 + 3sqrt(2))
={{{(1+4sqrt(10))/(1-3*sqrt(2))}}}
={{{(1+4*sqrt(10))*(1 + 3sqrt(2))/((1-3*sqrt(2))*(1 + 3sqrt(2)))}}}
={{{(1+4*sqrt(10))*(1 + 3sqrt(2))/19}}}
={{{(1 + 4sqrt(10) + 3sqrt(2) + 12sqrt(20))/19}}}
={{{(1 + 4sqrt(10) + 3sqrt(2) + 24sqrt(5))/19}}}