Question 173427
 Solve the equation:
logx27=2/3
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Assuming x is the base:
Put it into exponential form
{{{x^(2/3) = 27}}}
{{{x^2 = 27^3}}}
{{{x = sqrt(27^3)}}}
{{{x = 27*sqrt(27)}}}
{{{x = 81*sqrt(3)}}}