Question 173392
let x be the amount of gasoline added......the amount of oil must stay the same on the new mixture so
:
{{{(1/33)(2)=(1/41)(2+x)}}}
:
{{{2/33=(2+x)/41}}}
:
{{{2(41)=33(2+x)}}}
:
{{{82=66+33x}}}
:
{{{33x=16}}}
:
{{{highlight(x=16/33)}}}gal of gasoline to make 40 parts gasoline and 1 part oil
: