Question 173387


{{{(3x^2-6x-72)/(2x^2-8x-64)}}} Start with the given expression.



{{{(3(x+4)(x-6))/(2x^2-8x-64)}}} Factor {{{3x^2-6x-72}}} to get {{{3(x+4)(x-6)}}}.



{{{(3(x+4)(x-6))/(2(x+4)(x-8))}}} Factor {{{2x^2-8x-64}}} to get {{{2(x+4)(x-8)}}}.



{{{(3*highlight((x+4))(x-6))/(2*highlight((x+4))(x-8))}}} Highlight the common terms. 



{{{(3*cross((x+4))(x-6))/(2*cross((x+4))(x-8))}}} Cancel out the common terms. 



{{{(3(x-6))/(2(x-8))}}} Simplify. 



{{{(3x-18)/(2x-16)}}} Distribute



So {{{(3x^2-6x-72)/(2x^2-8x-64)}}} simplifies to {{{(3x-18)/(2x-16)}}}.