Question 173356
Solve by graphing.
3x + 4y ≤ 12
x + 3y ≤ 6
x ≥ 0
y ≥ 0
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Graph the boundaries:
y = 0
x = 0
y = -(1/3)x + 2
y = -(3/4)x +3
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Shade the area within the boundaries:
{{{graph(400,300,-10,10,-10,10,0,(-1/3)x+2,(-3/4)x+3)}}}
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Cheers,
Stan H.