Question 173315
 3x+2y=-6....eq 1
-2x+5y=23....eq 2

lets use the process of elimination which means we need to manipulate eq 1 and 2 such that one of the variables is eliminated.  There are various numbers we could multiply by the equations to reach this objective.  Lets multiply eq 1 by 5 and eq 2 by -2 so that the y terms will be eliminated 
:
15x+10y=-30...revised eq 1
 4x-10y=-46....revised eq 2
:
now observing  the equations we can see that when the equations are added to one another that the y terms are eliminated 10y-10y=0.  We are left with
15x+4x=-30-46
:
19x=-76
:
{{{highlight(x=-4)}}}
:
now we take x's found value and plug it back into any equation to find y's value. I choose eq 1
:
3(-4)+2y=-6
:
-12+2y=-6
:
2y=6
:
{{{highlight(y=3)}}}