Question 173300


{{{(11x+3y)(x+4y)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(11x)+3y)(highlight(x)+4y)}}} Multiply the <font color="red">F</font>irst terms:{{{(11*x)*(x)=11*x^2}}}.



{{{(highlight(11x)+3y)(x+highlight(4y))}}} Multiply the <font color="red">O</font>uter terms:{{{(11*x)*(4*y)=44*x*y}}}.



{{{(11x+highlight(3y))(highlight(x)+4y)}}} Multiply the <font color="red">I</font>nner terms:{{{(3*y)*(x)=3*x*y}}}.



{{{(11x+highlight(3y))(x+highlight(4y))}}} Multiply the <font color="red">L</font>ast terms:{{{(3*y)*(4*y)=12*y^2}}}.



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{{{11*x^2+44*x*y+3*x*y+12*y^2}}} Now collect every term to make a single expression.



{{{11*x^2+47*x*y+12*y^2}}} Now combine like terms.



So {{{(11x+3y)(x+4y)}}} FOILs to {{{11*x^2+47*x*y+12*y^2}}}.



In other words, {{{(11x+3y)(x+4y)=11*x^2+47*x*y+12*y^2}}}.