Question 173223
Use the quadratic formula to solve {{{2x^2+11x-4}}}
a=2 b=11 c=-4 (they are your coefficients)
so you would plug a b c in this formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
so we have
{{{x = (-11 +- sqrt( 11^2-4*2*(-4) ))/(2*2) }}} 
{{{x = (-11 +- sqrt( 121+32 ))/(4) }}} 
{{{x = (-11 +- sqrt( 153 ))/(4) }}} 
{{{x = (-11 +- 3*(sqrt( 17 )))/(4) }}}