Question 173225
How many real and imaginary soultions does the equation {{{4x^2+13x+7=0}}} have?
{{{(4x+7)(x+1)=0}}}
{{{4x+7=0}}}
{{{4x=-7}}}
{{{x=-7/4}}} that's one solution
{{{x+1=0}}}
{{{x=-1}}} that's second solution
so two total

How many real and imaginary soultions does the equation {{{2x^2-7x+9=x+1}}} have?
{{{2x^2-7x-x+9-1=0}}}
{{{2x^2-8x+8=0}}}
{{{2(x^2-4x+4)=0}}}
{{{2(x-2)(x-2)=0}}}
{{{x-2=0}}}
{{{x=2}}}  the other solution will be the same, so it only has one solution.